What is the derivative of f(x)=0.4x^{1.6} ?

The derivative of f(x)=0.4x^{1.6} is 0.64x^{0.6}

What is the first derivative of f(x)=0.4x^{1.6} ?

The first derivative of f(x)=0.4x^{1.6} is 0.64x^{0.6}

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derivative of

f (x) = 0.4 x^{1.6}

0.64 x^{0.6}

Solution steps

\frac{d}{d x} (0.4 x^{1.6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.4 \frac{d}{d x} (x^{1.6})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 0.4 \cdot 1.6 x^{1.6 - 1}

Simplify

= 0.64 x^{0.6}

(\frac{x - 2 ln ( x ) - 1}{x - 1})^{^{'}}

\int (x^{3} + e^{3 x}) d x

\frac{\partial}{\partial x} (4 x^{3} - 5 x y + y^{2})

y = - \frac{1}{x ^{2}}

\frac{d}{d x} (x^{7} e^{4 x})

What is the derivative of f(x)=0.4x^{1.6} ?
The derivative of f(x)=0.4x^{1.6} is 0.64x^{0.6}
What is the first derivative of f(x)=0.4x^{1.6} ?
The first derivative of f(x)=0.4x^{1.6} is 0.64x^{0.6}