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Popular >

y^'=2x+3y-1

Solution

y^{^{'}} = 2 x + 3 y - 1

Solution

y = - \frac{2 x}{3} + \frac{1}{9} + c_{1} e^{3 x}

Solution steps

y^{'} (x) = 2 x + 3 y - 1

Solve linear ODE:

y = - \frac{2 x}{3} + \frac{1}{9} + c_{1} e^{3 x}

y = - \frac{2 x}{3} + \frac{1}{9} + c_{1} e^{3 x}

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(\partial)/(\partial x)(1000e^{-x^2-2y^2-z^2})

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\int \frac{cos ( ln ( 9 x ) )}{x} d x

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\int (3 x - 2)^{- 11} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2x+3y-1 ?
The solution for y^'=2x+3y-1 is y=-(2x)/3+1/9+c_{1}e^{3x}