What is the derivative of f(x)= 1/(sqrt(x+1)) ?

The derivative of f(x)= 1/(sqrt(x+1)) is -1/(2(x+1)^{3/2)}

What is the first derivative of f(x)= 1/(sqrt(x+1)) ?

The first derivative of f(x)= 1/(sqrt(x+1)) is -1/(2(x+1)^{3/2)}

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derivative of

f (x) = \frac{1}{x + 1}

- \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 1)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 1)

= - \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= - \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}} \cdot 1

Simplify

= - \frac{1}{2 ( x + 1 ) ^{\frac{3}{2}}}

x \to \infty lim (y^{- x})

x \to 2 lim (5)

e^{- x}, 0, 0, ln (3)

\frac{d y}{d t} = 6 y + 2 t - 4, y (0) = 3

x \to 4 lim (\frac{x ^{2}}{x - 4})

What is the derivative of f(x)= 1/(sqrt(x+1)) ?
The derivative of f(x)= 1/(sqrt(x+1)) is -1/(2(x+1)^{3/2)}
What is the first derivative of f(x)= 1/(sqrt(x+1)) ?
The first derivative of f(x)= 1/(sqrt(x+1)) is -1/(2(x+1)^{3/2)}