What is the first (3sin(x))^' ?

The first (3sin(x))^' is 3cos(x)

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(3sin(x))^'

(3 sin (x))^{^{'}}

3 cos (x)

Solution steps

(3 sin (x))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 (sin (x))^{^{'}}

Apply the common derivative:

(sin (x))^{'} = cos (x)

= 3 cos (x)

\frac{\partial}{\partial z} (e^{x y z^{8}})

f (x) = 2 sin (x), g (x) = 2 cos (x)

y^{^{''}} + 2 y^{^{'}} + y = - 4 e^{- t}

y^{^{''}} + 9 y = 4 x e^{(2 x)}, y (0) = 0, y^{^{'}} (0) = 0

x \to 0 + lim (5 x + 9)