What is the derivative of 3x^3-5x^2+4 ?

The derivative of 3x^3-5x^2+4 is 9x^2-10x

What is the first derivative of 3x^3-5x^2+4 ?

The first derivative of 3x^3-5x^2+4 is 9x^2-10x

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\frac{d}{d x} (3 x^{3} - 5 x^{2} + 4)

9 x^{2} - 10 x

Solution steps

\frac{d}{d x} (3 x^{3} - 5 x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (4) = 0

= 9 x^{2} - 10 x + 0

Simplify

= 9 x^{2} - 10 x

x \to 2 - lim (\frac{1}{x - 3})

n = 2 \sum \infty 2 (- \frac{1}{2})^{n}

\frac{d}{d x} (\frac{1 + csc ( x ^{3} )}{1 - cot ( x ^{3} )})

\int \frac{1}{y - 5} d y

\int sin^{3} (2 x) cos^{4} (2 x) d x

What is the derivative of 3x^3-5x^2+4 ?
The derivative of 3x^3-5x^2+4 is 9x^2-10x
What is the first derivative of 3x^3-5x^2+4 ?
The first derivative of 3x^3-5x^2+4 is 9x^2-10x