What is (\partial)/(\partial x)(x^2+xy+y^2-6x+2) ?

The answer to (\partial)/(\partial x)(x^2+xy+y^2-6x+2) is 2x+y-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2+xy+y^2-6x+2)

\frac{\partial}{\partial x} (x^{2} + x y + y^{2} - 6 x + 2)

2 x + y - 6

Solution steps

\frac{\partial}{\partial x} (x^{2} + x y + y^{2} - 6 x + 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (6 x) + \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (6 x) = 6

\frac{\partial}{\partial x} (2) = 0

= 2 x + y + 0 - 6 + 0

Simplify

= 2 x + y - 6

\int \frac{e ^{2} x}{4 + e ^{4} x} d x

\frac{d y}{d x} = \frac{( 2 x + 1 )}{2 y}

9 x (2 x^{2} + 1)

\int (x ln (x))^{2} (\frac{1}{x ^{2}}) d x

2 x

What is (\partial)/(\partial x)(x^2+xy+y^2-6x+2) ?
The answer to (\partial)/(\partial x)(x^2+xy+y^2-6x+2) is 2x+y-6