What is the derivative of f(x)=2x^2-x ?

The derivative of f(x)=2x^2-x is 4x-1

What is the first derivative of f(x)=2x^2-x ?

The first derivative of f(x)=2x^2-x is 4x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 2 x^{2} - x

4 x - 1

Solution steps

\frac{d}{d x} (2 x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

= 4 x - 1

x d x + sin^{2} (\frac{y}{x}) (y d x - x d y) = 0

\int (r^{3} + 1)^{2} \cdot r^{2} d r

\int \frac{x ^{4} - x ^{3}}{x ^{5}} d x

\frac{d}{d x} (\frac{x ^{3} + 9}{x})

y^{^{'}} = \frac{y ^{3} + 1}{( 3 x y ^{2} )}

What is the derivative of f(x)=2x^2-x ?
The derivative of f(x)=2x^2-x is 4x-1
What is the first derivative of f(x)=2x^2-x ?
The first derivative of f(x)=2x^2-x is 4x-1