What is the derivative of f(x)=sqrt(4x+32) ?

The derivative of f(x)=sqrt(4x+32) is 1/(sqrt(x+8))

What is the first derivative of f(x)=sqrt(4x+32) ?

The first derivative of f(x)=sqrt(4x+32) is 1/(sqrt(x+8))

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derivative of

f (x) = 4 x + 32

\frac{1}{x + 8}

Solution steps

\frac{d}{d x} (4 x + 32)

Apply the chain rule:

\frac{1}{2 4 x + 32} \frac{d}{d x} (4 x + 32)

= \frac{1}{2 4 x + 32} \frac{d}{d x} (4 x + 32)

\frac{d}{d x} (4 x + 32) = 4

= \frac{1}{2 4 x + 32} \cdot 4

Simplify

\frac{1}{2 4 x + 32} \cdot 4 : \frac{1}{x + 8}

= \frac{1}{x + 8}

\frac{d}{d j} (i + j)

x^{2} y^{^{'}} + 3 x y = \frac{( sin ( 2 x ) )}{x}

x \to 8 lim (\frac{x - 9}{x - 8})

f (x) = ((25 - x^{2})^{\frac{1}{2}}), \frac{4}{3} x, 5

\frac{\partial}{\partial x} (a e^{2 x})

What is the derivative of f(x)=sqrt(4x+32) ?
The derivative of f(x)=sqrt(4x+32) is 1/(sqrt(x+8))
What is the first derivative of f(x)=sqrt(4x+32) ?
The first derivative of f(x)=sqrt(4x+32) is 1/(sqrt(x+8))