What is the limit as x approaches 1 of (4-x)/(x-1) ?

The limit as x approaches 1 of (4-x)/(x-1) is diverges

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limit as x approaches 1 of (4-x)/(x-1)

x \to 1 lim (\frac{4 - x}{x - 1})

diverges

Solution steps

x \to 1 lim (\frac{4 - x}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{4 - x}{x - 1}) = \infty

x \to 1 - lim (\frac{4 - x}{x - 1}) = - \infty

= diverges

\int (x + 1) \cdot e^{4 x + 1} d x

3 4 x - 5

\int 3 x^{2} - x d x

(6 y + 2 t - 7) d t + (4 y + 6 t - 1) d y = 0

x \to 1 lim (\frac{4}{( x - 1 ) ^{2}})

What is the limit as x approaches 1 of (4-x)/(x-1) ?
The limit as x approaches 1 of (4-x)/(x-1) is diverges