What is the integral from 0 to x of e^{-t^2} ?

The integral from 0 to x of e^{-t^2} is (sqrt(pi))/2 \erf(x)

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integral from 0 to x of e^{-t^2}

\int_{0}^{x} e^{- t^{2}} d t

\frac{π}{2} erf (x)

Solution steps

\int_{0}^{x} e^{- t^{2}} d t

Use the nonelementary integral:

\int e^{- t^{2}} d t = \frac{π}{2} erf (t)

= [\frac{π}{2} erf (t)]_{0}^{x}

Compute the boundaries:

\frac{π}{2} erf (x)

= \frac{π}{2} erf (x)

\frac{x + 1}{4 x ^{2} + 12 x + 2}

\frac{d}{d x} (3 arcsin (x^{2}))

\int_{1}^{2} 4^{x} d x

4 x^{2}, \frac{x}{2}

x \to 0 - lim (- x + 3)

What is the integral from 0 to x of e^{-t^2} ?
The integral from 0 to x of e^{-t^2} is (sqrt(pi))/2 \erf(x)