What is the integral from 0 to 2 of (x^2) ?

The integral from 0 to 2 of (x^2) is 8/3

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integral from 0 to 2 of (x^2)

\int_{0}^{2} (x^{2}) d x

\frac{8}{3}

Decimal

2.66666 \dots

Solution steps

\int_{0}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{2}

= [\frac{x ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= \frac{8}{3}

\frac{d N}{d t} = k (350 - N)

\frac{14 x + 6 x ^{2}}{( 7 + 6 x ) ^{2}}

\int \frac{1 + x}{1 + x ^{2}} d x

x \to 3 - lim (\frac{( 2 )}{x - 3})

x \to - \infty lim (e^{- 6 x} - 2 e^{- 2 x} - 1)

What is the integral from 0 to 2 of (x^2) ?
The integral from 0 to 2 of (x^2) is 8/3