What is the integral of 7^{x+2} ?

The integral of 7^{x+2} is (7^{x+2})/(ln(7))+C

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integral of 7^{x+2}

\int 7^{x + 2} d x

\frac{7 ^{x + 2}}{ln ( 7 )} + C

Solution steps

\int 7^{x + 2} d x

Simplify

7^{x + 2} : 7^{x} \cdot 7^{2}

= \int 7^{x} \cdot 7^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7^{2} \cdot \int 7^{x} d x

Simplify

= 49 \cdot \int 7^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= 49 \cdot \frac{7 ^{x}}{ln ( 7 )}

Simplify

49 \cdot \frac{7 ^{x}}{ln ( 7 )} : \frac{7 ^{x + 2}}{ln ( 7 )}

= \frac{7 ^{x + 2}}{ln ( 7 )}

Add a constant to the solution

= \frac{7 ^{x + 2}}{ln ( 7 )} + C

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What is the integral of 7^{x+2} ?
The integral of 7^{x+2} is (7^{x+2})/(ln(7))+C