What is the integral from 0 to 9 of x^2 ?

The integral from 0 to 9 of x^2 is 243

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integral from 0 to 9 of x^2

\int_{0}^{9} x^{2} d x

243

Solution steps

\int_{0}^{9} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{9}

= [\frac{x ^{3}}{3}]_{0}^{9}

Compute the boundaries:

243

= 243

x \frac{d y}{d x} - y = x

\frac{\partial}{\partial y} (y^{3} sin (4 x))

\frac{d}{d x} ((1 + 6 x^{2}) (x - x^{2}))

\int x csch^{2} (\frac{x ^{2}}{2}) d x

x = 2 y^{2}, x = y^{2} + 4

What is the integral from 0 to 9 of x^2 ?
The integral from 0 to 9 of x^2 is 243