What is the limit as x approaches 2 of sqrt(x+1) ?

The limit as x approaches 2 of sqrt(x+1) is square root of 3

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limit as x approaches 2 of sqrt(x+1)

x \to 2 lim (x + 1)

3

Decimal

1.73205 \dots

Solution steps

x \to 2 lim (x + 1)

Plug in the value

x = 2

= 2 + 1

Simplify

= 3

\int \frac{x ^{2}}{3 x ^{2} + 4} d x

\int 4 x^{3} + 9 sin (x) d x

x \to 3 lim (x + 1)

\int sech^{2} (x) d x

n = 1 \sum \infty n! (x + 1)^{n}

What is the limit as x approaches 2 of sqrt(x+1) ?
The limit as x approaches 2 of sqrt(x+1) is square root of 3