What is the limit as x approaches 0 of ((2+x)^2-4)/(h(x)) ?

The limit as x approaches 0 of ((2+x)^2-4)/(h(x)) is 0

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limit as x approaches 0 of ((2+x)^2-4)/(h(x))

x \to 0 lim (\frac{( 2 + x ) ^{2} - 4}{h ( x )})

0

Solution steps

x \to 0 lim (\frac{( 2 + x ) ^{2} - 4}{h ( x )})

Plug in the value

x = 0

, assuming the function is continuous at this point

= \frac{( 2 + 0 ) ^{2} - 4}{h ( 0 )}

Simplify

= 0

\frac{\partial}{\partial x} (2 - x^{2} + x y - 2 y^{2})

\frac{\partial}{\partial h ( w )} (\frac{w}{h ( w ) ^{2}})

2 e^{5 x} cos (6 x)

\frac{1}{2} (t - 2)^{2}

\frac{\partial}{\partial x} (4 y + x e^{\frac{x}{y}})

What is the limit as x approaches 0 of ((2+x)^2-4)/(h(x)) ?
The limit as x approaches 0 of ((2+x)^2-4)/(h(x)) is 0