What is the integral of 7sec^2(x) ?

The integral of 7sec^2(x) is 7tan(x)+C

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integral of 7sec^2(x)

\int 7 sec^{2} (x) d x

7 tan (x) + C

Solution steps

\int 7 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 7 tan (x)

Add a constant to the solution

= 7 tan (x) + C

\frac{d}{d x} (2 x^{2} - 1 + c e^{- 2 x^{2}})

\frac{\partial}{\partial x} (x yz + x^{3} + y^{4} + z^{5})

y^{^{''}} + y = t (1 + sin (t))

f (x) = x^{4} + x^{2} + 2

x \to 4 lim (\frac{a x ^{4}}{x - 4})