What is the tangent of 4-3x^3 ?

The tangent of 4-3x^3 is y=-9a_{0}^2x+4+6a_{0}^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 4-3x^3

tangent of

4 - 3 x^{3}

y = - 9 a_{0}^{2} x + 4 + 6 a_{0}^{3}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 4 - 3 a_{0}^{3})

Find the slope of

y = 4 - 3 x^{3} : \frac{d y}{d x} = - 9 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 9 a_{0}^{2}

Find the line with slope m=

- 9 a_{0}^{2}

and passing through

(a_{0}, 4 - 3 a_{0}^{3}) : y = - 9 a_{0}^{2} x + 4 + 6 a_{0}^{3}

y = - 9 a_{0}^{2} x + 4 + 6 a_{0}^{3}

\int \frac{2}{x 9 x ^{2} + 1} d x

y = \frac{3}{x ^{2}} - 8 4 x

\int \frac{x ^{2} + 5 x + 7}{x + 3} d x

\int y e^{4 y} d y

\frac{4 s e ^{- 3 s}}{( s ^{2} + 4 )}

What is the tangent of 4-3x^3 ?
The tangent of 4-3x^3 is y=-9a_{0}^2x+4+6a_{0}^3