What is the derivative of x-4\sqrt[3]{x} ?

The derivative of x-4\sqrt[3]{x} is 1-4/(3x^{2/3)}

What is the first derivative of x-4\sqrt[3]{x} ?

The first derivative of x-4\sqrt[3]{x} is 1-4/(3x^{2/3)}

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\frac{d}{d x} (x - 4 3 x)

1 - \frac{4}{3 x ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (x - 4 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (4 3 x)

\frac{d x}{d x} = 1

\frac{d}{d x} (4 3 x) = \frac{4}{3 x ^{\frac{2}{3}}}

= 1 - \frac{4}{3 x ^{\frac{2}{3}}}

\int \frac{1}{( 2 - x ) ^{2}} d x

\frac{d}{d x} ((ln (x^{2}))^{2})

2 x \frac{d y}{d x} = y + 1

x \to 0 lim (8 x + 4 h - 2)

\frac{\partial}{\partial x} (6 x^{2} + y^{2})

What is the derivative of x-4\sqrt[3]{x} ?
The derivative of x-4\sqrt[3]{x} is 1-4/(3x^{2/3)}
What is the first derivative of x-4\sqrt[3]{x} ?
The first derivative of x-4\sqrt[3]{x} is 1-4/(3x^{2/3)}