What is the solution for (dx}{dy}=(\frac{y+1)/x)2 ?

The solution for (dx}{dy}=(\frac{y+1)/x)2 is x=sqrt(2y^2+4y+c_{1)},x=-sqrt(2y^2+4y+c_{1)}

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(dx}{dy}=(\frac{y+1)/x)2

\frac{d x}{d y} = (\frac{y + 1}{x}) 2

x = 2 y^{2} + 4 y + c_{1}, x = - 2 y^{2} + 4 y + c_{1}

Solution steps

\frac{d x}{d y} = (\frac{y + 1}{x}) 2

Solve separable ODE:

x = 2 y^{2} + 4 y + c_{1}, x = - 2 y^{2} + 4 y + c_{1}

x = 2 y^{2} + 4 y + c_{1}, x = - 2 y^{2} + 4 y + c_{1}

\frac{( x + 1 ) d y}{d x} + (x + 2) y = 2 x e^{- x}

\frac{\partial}{\partial x} (sin (x y) + x + y)

\int 1 - sin (2 x) d x

n = 0 \sum \infty (- \frac{10}{11})^{n}

7 t \frac{d y}{d t} + y = 0, y (1) = 1

What is the solution for (dx}{dy}=(\frac{y+1)/x)2 ?
The solution for (dx}{dy}=(\frac{y+1)/x)2 is x=sqrt(2y^2+4y+c_{1)},x=-sqrt(2y^2+4y+c_{1)}