What is the tangent of 2x^2-3 ?

The tangent of 2x^2-3 is y=4a_{0}x-2a_{0}^2-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 2x^2-3

tangent of

2 x^{2} - 3

y = 4 a_{0} x - 2 a_{0}^{2} - 3

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} - 3)

Find the slope of

y = 2 x^{2} - 3 : \frac{d y}{d x} = 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a_{0}

Find the line with slope m=

4 a_{0}

and passing through

(a_{0}, 2 a_{0}^{2} - 3) : y = 4 a_{0} x - 2 a_{0}^{2} - 3

y = 4 a_{0} x - 2 a_{0}^{2} - 3

e^{- s}

y^{^{''}} - 2 y^{^{'}} - 3 y = - 5 t e^{- t}

f (x) = 12

x \to - 3 lim (x + 7)

\int ln (a^{2} + x^{2}) d x