What is (\partial)/(\partial x)(ln(2x+2)) ?

The answer to (\partial)/(\partial x)(ln(2x+2)) is 1/(x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(ln(2x+2))

\frac{\partial}{\partial x} (ln (2 x + 2))

\frac{1}{x + 1}

Solution steps

\frac{\partial}{\partial x} (ln (2 x + 2))

Apply the chain rule:

\frac{1}{2 x + 2} \frac{\partial}{\partial x} (2 x + 2)

= \frac{1}{2 x + 2} \frac{\partial}{\partial x} (2 x + 2)

\frac{\partial}{\partial x} (2 x + 2) = 2

= \frac{1}{2 x + 2} \cdot 2

Simplify

\frac{1}{2 x + 2} \cdot 2 : \frac{1}{x + 1}

= \frac{1}{x + 1}

\frac{d}{d x} (- \frac{3}{2 ( 1 + x ) ^{\frac{3}{2}}})

\frac{d}{d x} (1 ln (x) - \frac{x ^{2}}{8})

g (u) = 6 u + 5 u

\int \frac{4}{5} - \frac{1}{3 5 x} d x

\int 12 θ sec^{2} (θ) d θ

What is (\partial)/(\partial x)(ln(2x+2)) ?
The answer to (\partial)/(\partial x)(ln(2x+2)) is 1/(x+1)