What is the tangent of (2x-9)(x^2+6),\at x=3 ?

The tangent of (2x-9)(x^2+6),\at x=3 is y=12x-81

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tangent of (2x-9)(x^2+6),\at x=3

tangent of

(2 x - 9) (x^{2} + 6), at x = 3

y = 12 x - 81

Solution steps

Find the tangent point:

(3, - 45)

Find the slope of

y = (2 x - 9) (x^{2} + 6) : \frac{d y}{d x} = 6 x^{2} - 18 x + 12

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12

Find the line with slope m=

12

and passing through

(3, - 45) : y = 12 x - 81

y = 12 x - 81

\int_{0}^{6} 1

\int x - 7 + 8 x - x^{2} d x

x \to 7 lim (6 x^{- 1})

x \to 2 lim (3 x^{2} - 2 x + 4)

\int (x^{3} + x)^{8} (3 x^{2} + 1) d x

What is the tangent of (2x-9)(x^2+6),\at x=3 ?
The tangent of (2x-9)(x^2+6),\at x=3 is y=12x-81