What is the derivative of e^{-2x+x^2} ?

The derivative of e^{-2x+x^2} is e^{-2x+x^2}(-2+2x)

What is the first derivative of e^{-2x+x^2} ?

The first derivative of e^{-2x+x^2} is e^{-2x+x^2}(-2+2x)

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\frac{d}{d x} (e^{- 2 x + x^{2}})

e^{- 2 x + x^{2}} (- 2 + 2 x)

Solution steps

\frac{d}{d x} (e^{- 2 x + x^{2}})

Apply the chain rule:

e^{- 2 x + x^{2}} \frac{d}{d x} (- 2 x + x^{2})

= e^{- 2 x + x^{2}} \frac{d}{d x} (- 2 x + x^{2})

\frac{d}{d x} (- 2 x + x^{2}) = - 2 + 2 x

= e^{- 2 x + x^{2}} (- 2 + 2 x)

\int_{0}^{2} x - x d x

\frac{s}{( s ^{2} + 4 s + 5 )}

4 - x^{2}, - 2, 2

\int (x - 3) cos (x) d x

x \to 3 + lim (e^{\frac{x}{3 - x}})

What is the derivative of e^{-2x+x^2} ?
The derivative of e^{-2x+x^2} is e^{-2x+x^2}(-2+2x)
What is the first derivative of e^{-2x+x^2} ?
The first derivative of e^{-2x+x^2} is e^{-2x+x^2}(-2+2x)