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Popular >

y(x+3)+y^'=0,y(-6)=1

Solution

y (x + 3) + y^{^{'}} = 0, y (- 6) = 1

Solution

y = e^{- \frac{x ^{2}}{2} - 3 x}

Solution steps

y (x + 3) + y^{'} (x) = 0

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} - 3 x}

y = e^{- \frac{x ^{2}}{2} - 3 x}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y(x+3)+y^'=0,y(-6)=1 ?
The solution for y(x+3)+y^'=0,y(-6)=1 is y=e^{-(x^2)/2-3x}