What is the first d/(dt)(3sin(t)) ?

The first d/(dt)(3sin(t)) is 3cos(t)

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d/(dt)(3sin(t))

\frac{d}{d t} (3 sin (t))

3 cos (t)

Solution steps

\frac{d}{d t} (3 sin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (sin (t))

Apply the common derivative:

\frac{d}{d t} (sin (t)) = cos (t)

= 3 cos (t)

\int tan (x) d x

y = 9 + 5 x^{2} - 2 x^{3}

\int_{- 1}^{2} (x - 4 ∣ x ∣) d x

\frac{\partial}{\partial x} (\frac{x}{1 + x ^{2} + y ^{2}})

x \to 1 lim (- 2 x^{2} + 2 k)