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Popular >

area y=4x^2,y=4

Solution

area

y = 4 x^{2}, y = 4

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} 4 x^{2} - 4 d x

Solve

\int_{- 1}^{1} 4 x^{2} - 4 d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Graph

Popular Examples

limit as x approaches 2 of-x^2+4x-2

x \to 2 lim (- x^{2} + 4 x - 2)

integral of (9x^3)/(sqrt(x^2+1))

\int \frac{9 x ^{3}}{x ^{2} + 1} d x

integral of (2x-3)/(sqrt(x^2+6x+4))

\int \frac{2 x - 3}{x ^{2} + 6 x + 4} d x

derivative of 13e^x

\frac{d}{d x} (13 e^{x})

tangent of f(x)=((x^2))/(x-5),\at x=-3 tangent of

f (x) = \frac{( x ^{2} )}{x - 5}, at x = - 3

Frequently Asked Questions (FAQ)

What is area y=4x^2,y=4 ?
The answer to area y=4x^2,y=4 is 16/3