What is (\partial)/(\partial θ)(-cos(θ)) ?

The answer to (\partial)/(\partial θ)(-cos(θ)) is sin(θ)

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(\partial)/(\partial θ)(-cos(θ))

\frac{\partial}{\partial θ} (- cos (θ))

sin (θ)

Solution steps

\frac{\partial}{\partial θ} (- cos (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial θ} (cos (θ))

Apply the common derivative:

\frac{\partial}{\partial θ} (cos (θ)) = - sin (θ)

= - (- sin (θ))

Simplify

= sin (θ)

y = x, y = \frac{1}{3} x, x = 16

x \to 3 lim ((x^{2} + 4 x - 2)^{2})

\frac{d}{d a} ((x - a)^{2})

x \to 2 lim (x - 2)

f (x) = \frac{x}{1 + x ^{2}}, at x = 0

What is (\partial)/(\partial θ)(-cos(θ)) ?
The answer to (\partial)/(\partial θ)(-cos(θ)) is sin(θ)