What is laplacetransform 0.001t ?

The answer to laplacetransform 0.001t is (0.001)/(s^2)

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laplacetransform 0.001t

laplace transform

0.001 t

\frac{0.001}{s ^{2}}

Solution steps

L {0.001 t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 0.001 L {t}

L {t} : \frac{1}{s ^{2}}

= 0.001 \cdot \frac{1}{s ^{2}}

Refine

0.001 \frac{1}{s ^{2}} : \frac{0.001}{s ^{2}}

= \frac{0.001}{s ^{2}}

t y^{^{'}} = 4 y

(x^{2} + 1) y^{^{'}} + 4 x (y - 1) = 0, y (0) = 3

\frac{d y}{d x} + y^{3} x + 8 y = 0

\int sin^{5} (9 x) d x

\frac{d}{d x} (- \frac{2}{( x - 1 ) ^{2}})

What is laplacetransform 0.001t ?
The answer to laplacetransform 0.001t is (0.001)/(s^2)