What is the sum from n=1 to infinity of 1/(6n+5) ?

The sum from n=1 to infinity of 1/(6n+5) is diverges

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sum from n=1 to infinity of 1/(6n+5)

n = 1 \sum \infty \frac{1}{6 n + 5}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{6 n + 5}

Apply Series Limit Comparison Test:

diverges

= diverges

y^{^{'}} = \frac{( y ^{2} + 2 x y )}{x ^{2}}

\int e^{3 x} sin (3 x) d x

y^{^{'}} = \frac{x}{y}, y (0) = 3

x \to - 2 lim (3 x^{2} + 7 - \frac{1}{x})

\int \frac{1}{1 + ( cos ( x ) ) ^{2}} d x

What is the sum from n=1 to infinity of 1/(6n+5) ?
The sum from n=1 to infinity of 1/(6n+5) is diverges