What is the integral of (x-1)/(x^2+2) ?

The integral of (x-1)/(x^2+2) is 1/2 ln|x^2+2|-1/(sqrt(2))arctan(x/(sqrt(2)))+C

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integral of (x-1)/(x^2+2)

\int \frac{x - 1}{x ^{2} + 2} d x

\frac{1}{2} ln x^{2} + 2 - \frac{1}{2} arctan (\frac{x}{2}) + C

Solution steps

\int \frac{x - 1}{x ^{2} + 2} d x

Expand

\frac{x - 1}{x ^{2} + 2} : \frac{x}{x ^{2} + 2} - \frac{1}{x ^{2} + 2}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} + 2} d x - \int \frac{1}{x ^{2} + 2} d x

\int \frac{x}{x ^{2} + 2} d x = \frac{1}{2} ln x^{2} + 2

\int \frac{1}{x ^{2} + 2} d x = \frac{1}{2} arctan (\frac{x}{2})

= \frac{1}{2} ln x^{2} + 2 - \frac{1}{2} arctan (\frac{x}{2})

Add a constant to the solution

= \frac{1}{2} ln x^{2} + 2 - \frac{1}{2} arctan (\frac{x}{2}) + C

x \to 0 lim (\frac{( 7 x ^{2} - 2 x )}{x})

1 - cos (2 t)

x sin (y)

f^{^{'}} (x) = \frac{x}{8} - 1

y = 2 - x^{3}, P (1, 1)

What is the integral of (x-1)/(x^2+2) ?
The integral of (x-1)/(x^2+2) is 1/2 ln|x^2+2|-1/(sqrt(2))arctan(x/(sqrt(2)))+C