What is the tangent of y=x^2-6x,(5,-5) ?

The tangent of y=x^2-6x,(5,-5) is y=4x-25

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tangent of y=x^2-6x,(5,-5)

tangent of

y = x^{2} - 6 x, (5, - 5)

y = 4 x - 25

Solution steps

Find the slope of

y = x^{2} - 6 x : \frac{d y}{d x} = 2 x - 6

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(5, - 5) : y = 4 x - 25

y = 4 x - 25

\int (x^{2} - 2)^{3} d x

\int tan^{3} (x) cos (x) d x

\frac{tan ^{3} ( x )}{2 x + 1}

\frac{\partial}{\partial y} (x yz x)

- ln (1 - x^{2})

What is the tangent of y=x^2-6x,(5,-5) ?
The tangent of y=x^2-6x,(5,-5) is y=4x-25