What is the derivative of x/(753600x^2+900) ?

The derivative of x/(753600x^2+900) is -(2512x^2-3)/(300(2512x^2+3)^2)

What is the first derivative of x/(753600x^2+900) ?

The first derivative of x/(753600x^2+900) is -(2512x^2-3)/(300(2512x^2+3)^2)

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\frac{d}{d x} (\frac{x}{753600 x ^{2} + 900})

- \frac{2512 x ^{2} - 3}{300 ( 2512 x ^{2} + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{753600 x ^{2} + 900})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( 753600 x ^{2} + 900 ) - \frac{d}{d x} ( 753600 x ^{2} + 900 ) x}{( 753600 x ^{2} + 900 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (753600 x^{2} + 900) = 1507200 x

= \frac{1 \cdot ( 753600 x ^{2} + 900 ) - 1507200 xx}{( 753600 x ^{2} + 900 ) ^{2}}

Simplify

\frac{1 \cdot ( 753600 x ^{2} + 900 ) - 1507200 xx}{( 753600 x ^{2} + 900 ) ^{2}} : - \frac{2512 x ^{2} - 3}{300 ( 2512 x ^{2} + 3 ) ^{2}}

= - \frac{2512 x ^{2} - 3}{300 ( 2512 x ^{2} + 3 ) ^{2}}

y = 4 x + 4, y = 5 x + 5, x = 2

\int \frac{2 x - 1}{x ^{2} ( x + 3 )} d x

x \to 0 lim (\frac{( 2. 7 ^{x} - 1 )}{x})

\frac{d}{d t} (12 t - 40 π sin (π t))

\int_{0}^{8 π} t^{2} sin (2 t) d t

What is the derivative of x/(753600x^2+900) ?
The derivative of x/(753600x^2+900) is -(2512x^2-3)/(300(2512x^2+3)^2)
What is the first derivative of x/(753600x^2+900) ?
The first derivative of x/(753600x^2+900) is -(2512x^2-3)/(300(2512x^2+3)^2)