What is the derivative of tan(1/x) ?

The derivative of tan(1/x) is -(sec^2(1/x))/(x^2)

What is the first derivative of tan(1/x) ?

The first derivative of tan(1/x) is -(sec^2(1/x))/(x^2)

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derivative of

tan (\frac{1}{x})

- \frac{sec ^{2} ( \frac{1}{x} )}{x ^{2}}

Solution steps

\frac{d}{d x} (tan (\frac{1}{x}))

Apply the chain rule:

sec^{2} (\frac{1}{x}) \frac{d}{d x} (\frac{1}{x})

= sec^{2} (\frac{1}{x}) \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= sec^{2} (\frac{1}{x}) (- \frac{1}{x ^{2}})

Simplify

sec^{2} (\frac{1}{x}) (- \frac{1}{x ^{2}}) : - \frac{sec ^{2} ( \frac{1}{x} )}{x ^{2}}

= - \frac{sec ^{2} ( \frac{1}{x} )}{x ^{2}}

\frac{1}{2 - x}, 1

\frac{d}{d x} (\frac{3 x ^{3} + x + 2}{5 x ^{2} + 1})

\frac{\partial}{\partial x} (7 ln (x^{2} + y^{2}))

n = 5 \sum \infty \frac{1}{n}

x^{^{''}} - 5 x^{^{'}} + 6 x = e^{t}

What is the derivative of tan(1/x) ?
The derivative of tan(1/x) is -(sec^2(1/x))/(x^2)
What is the first derivative of tan(1/x) ?
The first derivative of tan(1/x) is -(sec^2(1/x))/(x^2)