What is the tangent of (2x-1)^2ln(2x-1),\at x=0 ?

The tangent of (2x-1)^2ln(2x-1),\at x=0 is y=(-4ln(-1)-2)x+Undefined

Popular >

tangent of (2x-1)^2ln(2x-1),\at x=0

tangent of

(2 x - 1)^{2} ln (2 x - 1), at x = 0

y = (- 4 ln (- 1) - 2) x + Undefined

Solution steps

Find the tangent point:

(0, Undefined)

Find the slope of

y = (2 x - 1)^{2} ln (2 x - 1) : \frac{d y}{d x} = 4 ln (2 x - 1) (2 x - 1) + 2 (2 x - 1)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4 ln (- 1) - 2

Find the line with slope m=

- 4 ln (- 1) - 2

and passing through

(0, Undefined) : y = (- 4 ln (- 1) - 2) x +

Undefined

y = (- 4 ln (- 1) - 2) x + Undefined

\frac{d}{d x} (3 x^{2} cos (x^{3}))

\frac{d y}{d t} + 3 y = cos (2 t)

\frac{1}{5 s + 2}

\frac{\partial}{\partial x} (sin^{3} (x - 5 y))

\frac{d}{d x} (30 x^{4} - 60 x^{3} + 60 x - 30)

What is the tangent of (2x-1)^2ln(2x-1),\at x=0 ?
The tangent of (2x-1)^2ln(2x-1),\at x=0 is y=(-4ln(-1)-2)x+Undefined