What is the derivative of x^2+1/(2x) ?

The derivative of x^2+1/(2x) is 2x-1/(2x^2)

What is the first derivative of x^2+1/(2x) ?

The first derivative of x^2+1/(2x) is 2x-1/(2x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} + \frac{1}{2 x})

2 x - \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (x^{2} + \frac{1}{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{1}{2 x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

= 2 x - \frac{1}{2 x ^{2}}

\int \frac{1}{ln ( y )} d y

\frac{d}{d x} (8 x + 1)

\int_{0}^{2} (x + 2)^{2} d x

f (x) = 6 x

\frac{d}{d x} (sinh (ln (x)))

What is the derivative of x^2+1/(2x) ?
The derivative of x^2+1/(2x) is 2x-1/(2x^2)
What is the first derivative of x^2+1/(2x) ?
The first derivative of x^2+1/(2x) is 2x-1/(2x^2)