What is laplacetransform cos(4t) ?

The answer to laplacetransform cos(4t) is s/(s^2+16)

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laplacetransform cos(4t)

laplace transform

cos (4 t)

\frac{s}{s ^{2} + 16}

Solution steps

L {cos (4 t)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (4 t)} = \frac{s}{s ^{2} + 4 ^{2}}

= \frac{s}{s ^{2} + 4 ^{2}}

= \frac{s}{s ^{2} + 16}

x \to 1 - lim (\frac{x - 1}{x + 1})

f (x) = \frac{x}{10}

\frac{d y}{d x}, x = y^{10}

\frac{\partial}{\partial x} (- \frac{x}{1 - x ^{2} y ^{2}})

\int e^{x} e^{x} - 1 d x

What is laplacetransform cos(4t) ?
The answer to laplacetransform cos(4t) is s/(s^2+16)