What is the derivative of 4x-3ln(x) ?

The derivative of 4x-3ln(x) is 4-3/x

What is the first derivative of 4x-3ln(x) ?

The first derivative of 4x-3ln(x) is 4-3/x

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\frac{d}{d x} (4 x - 3 ln (x))

4 - \frac{3}{x}

Solution steps

\frac{d}{d x} (4 x - 3 ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (3 ln (x))

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3 ln (x)) = \frac{3}{x}

= 4 - \frac{3}{x}

x \to - 2 lim (∣ ln ∣ x + 2 ∣ ∣)

x^{2} + 2, - x, 0, 1

\int \frac{2 cot ( x ) - 3 sin ^{2} ( x )}{sin ( x )} d x

x \to \infty lim (\frac{2170}{1 + e ^{- 0.156 x}})

\int 1 0^{5 x - 1} d x

What is the derivative of 4x-3ln(x) ?
The derivative of 4x-3ln(x) is 4-3/x
What is the first derivative of 4x-3ln(x) ?
The first derivative of 4x-3ln(x) is 4-3/x