What is the solution for y^'sin(5pix)=piycos(5pix) ?

The solution for y^'sin(5pix)=piycos(5pix) is y=c_{1}\sqrt[5]{sin(5pix)}

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y^'sin(5pix)=piycos(5pix)

y^{^{'}} sin (5 π x) = π y cos (5 π x)

y = c_{1} 5 sin (5 π x)

Solution steps

y^{'} (x) sin (5 π x) = π y cos (5 π x)

Solve separable ODE:

y = c_{1} 5 sin (5 π x)

y = c_{1} 5 sin (5 π x)

\frac{d}{d x} (2000)

y^{^{''}} + 4 y = cos (2 t)

\int t (t^{2} + 1)^{3} d t

x \to 10 lim (2^{\frac{1}{x - 10}})

y^{^{'}} = \frac{y ^{2}}{1 + y ^{2}}

What is the solution for y^'sin(5pix)=piycos(5pix) ?
The solution for y^'sin(5pix)=piycos(5pix) is y=c_{1}\sqrt[5]{sin(5pix)}