What is the integral from 0 to 2 of 10^x ?

The integral from 0 to 2 of 10^x is (99)/(ln(10))

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integral from 0 to 2 of 10^x

\int_{0}^{2} 1 0^{x} d x

\frac{99}{ln ( 10 )}

Decimal Notation

42.99515 \dots

Solution steps

\int_{0}^{2} 1 0^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{1 0 ^{x}}{ln ( 10 )}]_{0}^{2}

Compute the boundaries:

\frac{99}{ln ( 10 )}

= \frac{99}{ln ( 10 )}

\frac{d}{d x} (e^{3 x} - 1 - 3 x)

f (x) = \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 )}

\frac{d}{d x} (x^{5} - 20 x^{3} + 64 x)

\frac{d}{d x} (\frac{10 x ^{3}}{x ^{2} - 1})

What is the integral from 0 to 2 of 10^x ?
The integral from 0 to 2 of 10^x is (99)/(ln(10))