What is area f(x)=x^2-12,g(x)=4x ?

The answer to area f(x)=x^2-12,g(x)=4x is 256/3

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area f(x)=x^2-12,g(x)=4x

area

f (x) = x^{2} - 12, g (x) = 4 x

\frac{256}{3}

Decimal

85.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{6} x^{2} - 12 - 4 x d x

Solve

\int_{- 2}^{6} x^{2} - 12 - 4 x d x : \frac{256}{3}

The area is:

= \frac{256}{3}

\frac{d}{d x} (\frac{cos ( x ) - 1}{x})

y^{^{''}} - 12 y + 36 y = 0

\frac{( e ^{- 1 - x} - e ^{- 1} )}{x}

\int_{1}^{3} \frac{5}{x ^{2} + 2 x + 1} d x

f (x) = ln (5 - x)

What is area f(x)=x^2-12,g(x)=4x ?
The answer to area f(x)=x^2-12,g(x)=4x is 256/3