Solution
Solution
Solution steps
Treat as constants
Take the constant out:
Apply the Power Rule:
Simplify
Popular Examples
y^{''}+4y^'+20y=0,y(0)=4,y^'(0)=-7integral from-infinity to 0 of 6^r(dy)/(dt)+ay=be^{-bt}derivative of ((x-4(x^2+4x+16))/(x^3))integral of 1/(e^x+4)
Frequently Asked Questions (FAQ)
What is (\partial)/(\partial x)(5x^6sin(3y^4z^2)) ?
The answer to (\partial)/(\partial x)(5x^6sin(3y^4z^2)) is 30x^5sin(3y^4z^2)