What is the solution for 2(12)(18)+2(9)(dy)/(dt)=0 ?

The solution for 2(12)(18)+2(9)(dy)/(dt)=0 is y=-24t+c_{1}

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2(12)(18)+2(9)(dy)/(dt)=0

2 (12) (18) + 2 (9) \frac{d y}{d t} = 0

y = - 24 t + c_{1}

Solution steps

2 (12) (18) + 2 (9) \frac{d y}{d t} = 0

Substitute

\frac{d y}{d t}

with

y^{'} (t)

2 (12) (18) + 2 (9) y^{^{'}} (t) = 0

Isolate

y^{'} (t) : y^{'} (t) = - 24

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 24 d t

\int - 24 d t = - 24 t + c_{1}

y = - 24 t + c_{1}

\int cos (2 x) sin (4 x) d x

\frac{d y}{d t} = 25 t^{4}

\frac{\frac{d y}{d t} - e ^{- t} + 6}{y} = - 6, y (0) = - 2

\int cos (2 x) sin^{2} (x) d x

y^{^{'}} = \frac{6 x - 12}{x ^{2}}, y (1) = 20

What is the solution for 2(12)(18)+2(9)(dy)/(dt)=0 ?
The solution for 2(12)(18)+2(9)(dy)/(dt)=0 is y=-24t+c_{1}