What is the derivative of 3x+2e^x ?

The derivative of 3x+2e^x is 3+2e^x

What is the first derivative of 3x+2e^x ?

The first derivative of 3x+2e^x is 3+2e^x

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\frac{d}{d x} (3 x + 2 e^{x})

3 + 2 e^{x}

Solution steps

\frac{d}{d x} (3 x + 2 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (2 e^{x})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

= 3 + 2 e^{x}

\int_{0}^{1} 2 tan (\frac{π}{4} y) d y

\int 16 y d y

\int 2 x (x^{2} + 4)^{6} d x

\int e^{- s t} t e^{4 t} d t

y^{^{'}} = \frac{1}{t y}

What is the derivative of 3x+2e^x ?
The derivative of 3x+2e^x is 3+2e^x
What is the first derivative of 3x+2e^x ?
The first derivative of 3x+2e^x is 3+2e^x