What is the derivative of y=(7-x^2)(x^3-5x+2) ?

The derivative of y=(7-x^2)(x^3-5x+2) is -5x^4+36x^2-4x-35

What is the first derivative of y=(7-x^2)(x^3-5x+2) ?

The first derivative of y=(7-x^2)(x^3-5x+2) is -5x^4+36x^2-4x-35

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derivative of

y = (7 - x^{2}) (x^{3} - 5 x + 2)

- 5 x^{4} + 36 x^{2} - 4 x - 35

Solution steps

\frac{d}{d x} ((7 - x^{2}) (x^{3} - 5 x + 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 7 - x^{2}, g = x^{3} - 5 x + 2

= \frac{d}{d x} (7 - x^{2}) (x^{3} - 5 x + 2) + \frac{d}{d x} (x^{3} - 5 x + 2) (7 - x^{2})

\frac{d}{d x} (7 - x^{2}) = - 2 x

\frac{d}{d x} (x^{3} - 5 x + 2) = 3 x^{2} - 5

= (- 2 x) (x^{3} - 5 x + 2) + (3 x^{2} - 5) (7 - x^{2})

Simplify

(- 2 x) (x^{3} - 5 x + 2) + (3 x^{2} - 5) (7 - x^{2}) : - 5 x^{4} + 36 x^{2} - 4 x - 35

= - 5 x^{4} + 36 x^{2} - 4 x - 35

\frac{d}{d K} ((K^{a} L^{0.5})^{Y (K)})

\frac{d ^{3}}{d x ^{3}} (6 t + 8)

\frac{d}{d x} (sin^{3} (x) cos^{2} (x))

x \to 0 - lim (coth (x))

f (x) = x^{2} + 5, (- 3, 14)

What is the derivative of y=(7-x^2)(x^3-5x+2) ?
The derivative of y=(7-x^2)(x^3-5x+2) is -5x^4+36x^2-4x-35
What is the first derivative of y=(7-x^2)(x^3-5x+2) ?
The first derivative of y=(7-x^2)(x^3-5x+2) is -5x^4+36x^2-4x-35