What is the derivative of 4ax-x ?

The derivative of 4ax-x is 4a-1

What is the first derivative of 4ax-x ?

The first derivative of 4ax-x is 4a-1

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derivative of

4 a x - x

4 a - 1

Solution steps

\frac{d}{d x} (4 a x - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 a x) - \frac{d x}{d x}

\frac{d}{d x} (4 a x) = 4 a

\frac{d x}{d x} = 1

= 4 a - 1

f (x) = \frac{5 x + 1}{5 x ^{2} + 1}

\int \frac{2}{x ( 1 + 2 x ) ^{4}} d x

f^{^{'}} (x) = 0

\int_{- 1}^{1} e^{y} - (y^{2} - 8) d y

f (x) = \frac{1}{x}, at x = - 4