What is the solution for -(y^2}{t^2}dt+\frac{2y)/t dy=0 ?

The solution for -(y^2}{t^2}dt+\frac{2y)/t dy=0 is y=c_{1}sqrt(t)

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-(y^2}{t^2}dt+\frac{2y)/t dy=0

- \frac{y ^{2}}{t ^{2}} d t + \frac{2 y}{t} d y = 0

y = c_{1} t

Solution steps

- \frac{y ^{2}}{t ^{2}} d t + \frac{2 y}{t} d y = 0

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y = c_{1} t

y = c_{1} t

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What is the solution for -(y^2}{t^2}dt+\frac{2y)/t dy=0 ?
The solution for -(y^2}{t^2}dt+\frac{2y)/t dy=0 is y=c_{1}sqrt(t)