What is factor 3x^4+2x^3+x^2-2 ?

The solution to factor 3x^4+2x^3+x^2-2 is (x+1)(3x^3-x^2+2x-2)

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factor 3x^4+2x^3+x^2-2

factor

3 x^{4} + 2 x^{3} + x^{2} - 2

(x + 1) (3 x^{3} - x^{2} + 2 x - 2)

Solution steps

3 x^{4} + 2 x^{3} + x^{2} - 2

Use the rational root theorem

= (x + 1) \frac{3 x ^{4} + 2 x ^{3} + x ^{2} - 2}{x + 1}

\frac{3 x ^{4} + 2 x ^{3} + x ^{2} - 2}{x + 1} = 3 x^{3} - x^{2} + 2 x - 2

= (x + 1) (3 x^{3} - x^{2} + 2 x - 2)

(x^{2} - 1) y^{^{'}} = x y

\int x sin (6 x) d x

y = 3 x, y = 2 x^{2}

\int \frac{1}{x 9 x ^{2} + 25} d x

3 y^{^{''}} - 8 y^{^{'}} - 3 y = 0

What is factor 3x^4+2x^3+x^2-2 ?
The solution to factor 3x^4+2x^3+x^2-2 is (x+1)(3x^3-x^2+2x-2)