What is the solution for (d^2y)/(dx^2)+4y=0 ?

The solution for (d^2y)/(dx^2)+4y=0 is y=c_{1}cos(2x)+c_{2}sin(2x)

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(d^2y)/(dx^2)+4y=0

\frac{d ^{2} y}{d x ^{2}} + 4 y = 0

y = c_{1} cos (2 x) + c_{2} sin (2 x)

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 4 y = 0

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x)

(f (x) (2 x))^{'}

x \to - 8 lim (x + 8)

\frac{\partial}{\partial x} (\frac{y}{z} + \frac{z}{x} - \frac{x z}{y})

\int \frac{x}{x ^{2} + 2 x + 5} d x

\int \frac{1}{4 x - 3} d x

What is the solution for (d^2y)/(dx^2)+4y=0 ?
The solution for (d^2y)/(dx^2)+4y=0 is y=c_{1}cos(2x)+c_{2}sin(2x)