What is the tangent of f(x)=x^4+3e^x,(0,3) ?

The tangent of f(x)=x^4+3e^x,(0,3) is y=3x+3

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tangent of f(x)=x^4+3e^x,(0,3)

tangent of

f (x) = x^{4} + 3 e^{x}, (0, 3)

y = 3 x + 3

Solution steps

Find the slope of

f (x) = x^{4} + 3 e^{x} : \frac{df ( x )}{d x} = 4 x^{3} + 3 e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(0, 3) : y = 3 x + 3

y = 3 x + 3

\frac{\partial}{\partial y} ((x y)^{\frac{1}{2}})

\frac{1}{8 y ^{2}}

\frac{d}{d x} ((arctan (6 x))^{2})

x^{2} sin^{8} (x) + x cos^{- 3} (x)

f (x) = 2 x - 5

What is the tangent of f(x)=x^4+3e^x,(0,3) ?
The tangent of f(x)=x^4+3e^x,(0,3) is y=3x+3