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Popular >

y^'= 1/(1+x)

Solution

y^{^{'}} = \frac{1}{1 + x}

Solution

y = ln (1 + x) + c_{1}

Solution steps

y^{'} (x) = \frac{1}{1 + x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{1 + x} d x

\int \frac{1}{1 + x} d x = ln (1 + x) + c_{1}

y = ln (1 + x) + c_{1}

Popular Examples

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\int x^{3} x^{2} - 16 d x

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\frac{d}{d x} (5 - ∣ x ∣)

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\int tan (3 x se) c^{2} 3 x d x

limit as x approaches-3 of sqrt(x^2+x)-x

x \to - 3 lim (x^{2} + x - x)

integral from 0 to 1 of x/(x^3+1)

\int_{0}^{1} \frac{x}{x ^{3} + 1} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'= 1/(1+x) ?
The solution for y^'= 1/(1+x) is y=ln(1+x)+c_{1}